everytime you win a cycle,,you win 5 or 10bucks right? but the 9 cycles you lose to the end you lose 160 bucks or am i looking at this wrong?? seems like you have better odds of putting 5 on a color and trying to let it ride for a while..if you lose you lose 5 but if it doubles 5x=160 6x=320 7x=640 8x=1280 etc.. not very likely that happens but you only lose 5 bucks each time you miss. ive never done this so i cant say if it would work or not but it would take hours to lose 100,,,drink up
0
everytime you win a cycle,,you win 5 or 10bucks right? but the 9 cycles you lose to the end you lose 160 bucks or am i looking at this wrong?? seems like you have better odds of putting 5 on a color and trying to let it ride for a while..if you lose you lose 5 but if it doubles 5x=160 6x=320 7x=640 8x=1280 etc.. not very likely that happens but you only lose 5 bucks each time you miss. ive never done this so i cant say if it would work or not but it would take hours to lose 100,,,drink up
It is based on betting on the outside columns.For example:
1 ¨C 12
13 ¨C 25
25 ¨C 32
Or the 1st, 2nd, 3rd Column
These bets pay 2 to 1
You bet on a matrix system:
5return 10
5return 5
10return 10
20return 20
40return 40
80return 80
80 + 40 + 20 + 10 + 5 +10 / 6 = 27.5
The average win through the matrix is $27.50.
The probability of going through the full 6 round cycle is approximately 9%.
.6757 x .6757 x .6757 x .6757 x .6757 x .6757 = approx.9% of losing 6 in a row
12 winners out of 33 possible = .6757 chance of losing
So if you bet 100 times:
You will win:91 times ($2,502.50
You will lose:9 times ($1,440.00) ¨C 160 per cycle x 9
Therefore you will net a profit of $1,062.50 per 100 times you complete a cycle
Everyone please check my math¡ but so far.. I¡¯ve been profitable
Well you have some typos but your math is right. There are 36 numbers and then the 0. So it should read
1-12 13-24 25-36
and
12 winners out of 37 possible = .6757 chance of losing
Also the MAIN problem is that a roulette ball doesn't have a memory. It is not like blackjack where you can count cards and gain an edge because the probability of certain cards to come depend on the cards that came previously in the shoe. With roulette there is nothing that says just because 17 came that it can't come again immediately after it. I know guys that have tried this "system" with red/black. The longest string of reds I have seen hit in a row is 18! They happened to be betting on black at the time that this string of reds came so they kept doubleing and losing.
If you have won some money doing this I would stop now while you are ahead. In the long run roulette is -EV and no matter what system you try to employee, you will end up losing.
0
Quote Originally Posted by MJLaw:
It is based on betting on the outside columns.For example:
1 ¨C 12
13 ¨C 25
25 ¨C 32
Or the 1st, 2nd, 3rd Column
These bets pay 2 to 1
You bet on a matrix system:
5return 10
5return 5
10return 10
20return 20
40return 40
80return 80
80 + 40 + 20 + 10 + 5 +10 / 6 = 27.5
The average win through the matrix is $27.50.
The probability of going through the full 6 round cycle is approximately 9%.
.6757 x .6757 x .6757 x .6757 x .6757 x .6757 = approx.9% of losing 6 in a row
12 winners out of 33 possible = .6757 chance of losing
So if you bet 100 times:
You will win:91 times ($2,502.50
You will lose:9 times ($1,440.00) ¨C 160 per cycle x 9
Therefore you will net a profit of $1,062.50 per 100 times you complete a cycle
Everyone please check my math¡ but so far.. I¡¯ve been profitable
Well you have some typos but your math is right. There are 36 numbers and then the 0. So it should read
1-12 13-24 25-36
and
12 winners out of 37 possible = .6757 chance of losing
Also the MAIN problem is that a roulette ball doesn't have a memory. It is not like blackjack where you can count cards and gain an edge because the probability of certain cards to come depend on the cards that came previously in the shoe. With roulette there is nothing that says just because 17 came that it can't come again immediately after it. I know guys that have tried this "system" with red/black. The longest string of reds I have seen hit in a row is 18! They happened to be betting on black at the time that this string of reds came so they kept doubleing and losing.
If you have won some money doing this I would stop now while you are ahead. In the long run roulette is -EV and no matter what system you try to employee, you will end up losing.
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