Can Someone with skills help me...

After reading the article, I basically found out the same thing I already knew--a 2 team parlay has only 4 possible combinations--one of them will be right.  Then it talked alot about odds and how they always make a profit.  But the example used only a 2 or 3 team parlay where the house will most certainly come out ahead.

But, as you add more teams to the parlay...the win amount goes up...and if you add over 6...it really starts to move.  So as the payouts go up, you have the ability to bet more and more possible parlay combinations (just like when we had 2 or 3, but were taking a loss), with higher payouts...my question is...can all the different parlay combinations be bet using let's say $1...and there be a point where the player would be able to profit...

On a side note: I checked and...a $1 bet on a 12-team parlay would pay $1800.00...too bad I don't know the point total for every NFL game this week. lol

NVM...I finally got it. lol

I was confusing myself so much.  Guess it's not really ever possible guarantee that you get them all right, and at the same time make a profit.

However, this could be used on parlays where you felt really confident about 2 or 3 picks and you wanted to throw in other picks you were not sure about.  Then just pick the same 2 or 3 in the all parlays (and hope you were right) and then use different combinations for the other picks you were not as sure on.  Maybe that would work.  But guess there could always be upsets that would change everything.

  I get it now!   

Somebody please tell me I didnt just take 15 minutes of my life to read this thread.

@After_I_Win

 Did you find anything out 

throwback thread  

Someone has thought of money laundering....

@Dude15

I am intrigued by After_ I am a degenerate and didn¡¯t know someone else has the same idea I did. It works ! 

@After_I_Win

 Idk if you are alive still bet or use this account but its simple algebra permutations and combinations thier are online website that give you a list

@After_I_Win

 It works 7 team parlay is 128 different combinations of a 7 team parlay and atleast one underdog on the board you will make expected for if it¡¯s of 62$ if you are betting 1$ on each combination

@After_I_Win

 For 5 game parlay there¡¯s 36 combos 1$ each will have a 29$ loss with a 85$ win witch will leave your profits at around the 50$ area the point is to play 5 games that all have a underdog and atleast one team with a hit underdog that you think will hit put those five teams at 1$ each 

 So does anyone know if it is possible to cover all possible outcomes of a 6 team parlay? And how many parlays would it take to have a correct combination in one of them?

Here is the math.

For 110 110

2 teams 2 squared 4. 

This bet loses. Because of the juice.

So 3

2 cubed 2x2x2 one in 8

4 teams 

2x2x2x2 2 to the 4th 1 in 16

2x2x2x2x2 2 to the 5th power 1/32

2x2x2x2x2x2 2 to the 6th 1 /64

Ect.....

If the odds are offset say horses. And a 1/8 wins the first race on a 6 race ticket as example implied odds and actual 50/50 greatly exaggerated to add value in bets....